((5)/(6))^(4x)=((36)/(25))^(9-x)

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Solution for ((5)/(6))^(4x)=((36)/(25))^(9-x) equation: 



((5)/(6))^(4x)=((36)/(25))^(9-x)

We move all terms to the left:

((5)/(6))^(4x)-(((36)/(25))^(9-x))=0



Domain of the equation: 6)^4x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 25)^(9-x))!=0

x∈R



We add all the numbers together, and all the variables

(+5/6)^4x-((+36/25)^(-1x+9))=0

We calculate fractions


(125^(-1x+9)))/6^4x*25)^(-1x+9)))+(-216^4x/6^4x*25)^(-1x+9)))=0



We calculate terms in parentheses: +(125^(-1x+9)))/6^4x*25)^(-1x+9)))+(-216^4x/6^4x*25)^(-1x+9))), so:

125^(-1x+9)))/6^4x*25)^(-1x+9)))+(-216^4x/6^4x*25)^(-1x+9))

We can not solve this equation

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